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(C) $I. XeF_5^-$: Central atom $Xe$ has $8$ valence electrons. It forms $5$ bonds with $F$ and has $1$ negative charge,total $9$ electrons. $5$ are us

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$I$ and $II$

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(C) $I. XeF_5^-$: Central atom $Xe$ has $8$ valence electrons. It forms $5$ bonds with $F$ and has $1$ negative charge,total $9$ electrons. $5$ are used in bonding,leaving $4$ electrons,which equals $2$ lone pairs.$II. BrF_3$: Central atom $Br$ has $7$ valence electrons. $3$ are used in bonding with $F$,leaving $4$ electrons,which equals $2$ lone pairs.$III. XeF_2$: Central atom $Xe$ has $8$ valence electrons. $2$ are used in bonding,leaving $6$ electrons,which equals $3$ lone pairs.$IV. H_3S^{+}$: Central atom $S$ has $6$ valence electrons. $3$ are used in bonding with $H$,and $1$ is lost due to positive charge,leaving $2$ electrons,which equals $1$ lone pair.$V. CH_2$: Central atom $C$ has $4$ valence electrons. $2$ are used in bonding with $H$,leaving $2$ non-bonding electrons (radical),which equals $0$ lone pairs.Thus,$XeF_5^-$ and $BrF_3$ both have $2$ lone pairs.

List-$I$	List-$II$
$a$. See-Saw Shape	$i$. $XeF_4$
$b$. Square Pyramidal	$ii$. $ClF_3$
$c$. $T$-Shape	$iii$. $PbCl_2$
$d$. Bent Shape	$iv$. $SF_4$
	$v$. $BrF_5$

List-$I$ Molecule/ion	List-$II$ Bond pair : lone pair (on the central atom)
$A. ICl_2^-$	$I. 4 : 2$
$B. H_2O$	$II. 4 : 1$
$C. SO_2$	$III. 2 : 3$
$D. XeF_4$	$IV. 2 : 2$

Which of the following compounds have the same number of lone pairs on their central atom?
$I. XeF_5^- \quad II. BrF_3 \quad III. XeF_2 \quad IV. H_3S^{+} \quad V. CH_2$ (Methylene)

Similar Questions

Match the following:
List-$I$ List-$II$
$a$. See-Saw Shape $i$. $XeF_4$
$b$. Square Pyramidal $ii$. $ClF_3$
$c$. $T$-Shape $iii$. $PbCl_2$
$d$. Bent Shape $iv$. $SF_4$
$v$. $BrF_5$

The correct answer is

Match the List-$I$ with List-$II$.

List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom)

$A. ICl_2^-$ $I. 4 : 2$

$B. H_2O$ $II. 4 : 1$

$C. SO_2$ $III. 2 : 3$

$D. XeF_4$ $IV. 2 : 2$

Choose the correct answer from the options given below:

What is the $\angle HOH$ bond angle in the $H_2O$ molecule?

In a $AX_2L_n$ compound,if $X$ is a bond pair and $n$ is the number of lone pairs of electrons,which of the following options is incorrect?

The bond angle in a water molecule is nearly or directed bonds in water form an angle of:

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Which of the following compounds have the same number of lone pairs on their central atom?$I. XeF_5^- \quad II. BrF_3 \quad III. XeF_2 \quad IV. H_3S^{+} \quad V. CH_2$ (Methylene)